Question
9 litre of milk is taken out from a container and
replaced by water. This process is repeated once more, the ratio of quantity in container (M:W) is 16 : 9. Now find the initial quantity of milk in the container?Solution
Let the initial quantity of milk in the container was = 25x So 25x (1- 9/25x)^n = 16x ((25x-9)/25x)^2= 16x/25x (25x-9)/25x = √(16/25) (25x-9)/25x = 4/5 25x - 9 = 20x 5x = 9 x = 9/5 So initial quantity of milk = 25x = 25 × 9/5 = 45 litre
More Mixture Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
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