Question
9 litre of milk is taken out from a container and
replaced by water. This process is repeated once more, the ratio of quantity in container (M:W) is 16 : 9. Now find the initial quantity of milk in the container?Solution
Let the initial quantity of milk in the container was = 25x So 25x (1- 9/25x)^n = 16x ((25x-9)/25x)^2= 16x/25x (25x-9)/25x = √(16/25) (25x-9)/25x = 4/5 25x - 9 = 20x 5x = 9 x = 9/5 So initial quantity of milk = 25x = 25 × 9/5 = 45 litre
More Mixture Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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