Question
A 40-litre solution contains milk and water in the ratio
3 : 1. How many litres of water must be added to this solution so that the resulting mixture has milk and water in the ratio 3 : 2?Solution
ATQ, Total solution = 40 L Ratio (milk : water) = 3 : 1 Milk = 3/4 Γ 40 = 30 L Water = 1/4 Γ 40 = 10 L Let x litres of water be added. Then milk = 30 L, water = 10 + x L New ratio milk : water = 3 : 2 So, 30 : (10 + x) = 3 : 2 30 / (10 + x) = 3 / 2 Cross-multiply: 60 = 30 + 3x 3x = 30 β x = 10 Water to be added = 10 litres
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