Question
A container contains Alcohol and water in ratio of 4:3
and Capacity of Container is 28 lit. If half of the Container is replaced with 25 lit of water then find new quantity of water in container?Solution
Quantity of water remained in Container = 14 × 1/7 = 6 lit New quantity of water = 6 + 25 = 31 lit
More Mixture Questions
If 8x3 - 125y3 = (2x - Ay) X (Bx2 + 25y2 + Cxy), then find the value of 3 X (2A + 6B) - 2C.
‘a’ is directly proportional to ‘b’. If at a=30, the value of ‘b’ is 20% greater than ‘a’, then find the value of ‘a’ when b=54.
...Suppose xy = -15 and (x² + y²) = 34, then determine the value of (x – y).
- If (x 2 = 2x – 1), then find the value of [x³ + (x⁴/1)][1 - x³]
(x + 4) 2 + (y – 1) 2 + (z + 2) 2 = 0, then find the value of 2x - 3y + z.
Solve for x:- 5(x − 2)/3 = 3(x + 4)/2
Fing the value of:
[(1024)(n/5) × (4)(2n+1) ] / [(16)n × (4)(n-1) ]
If
= 3 then If (10 a³ + 4b³): (11a³ — 15b³) = 7:5, then (3a + 5b): (9a - 2b) = ?
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