Question
200 litres of mixture ‘A’ contains milk and water
in it. If mixture ‘A’ is mixed with 600 litres of mixture ‘B’ which contains water and salt, then the ratio of quantity of milk, water and salt in the final mixture will be 1:5:4, respectively. Find the difference between quantity of water in mixture ‘A’ and mixture ‘B’.Solution
Total quantity of mixture = 200 + 600 = 800 litres Quantity of milk in final mixture = (1/10) × 800 = 80 litres Quantity of water in mixture ‘A’ = 200 − 80 = 120 litres Quantity of salt in mixture ‘B’ = (4/10) × 800 = 320 litres Quantity of water in mixture ‘B’ = 600 − 320 = 280 litres Required difference = 280 − 120 = 160 litres
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