Question
A container holds milk and water in the ratio 5:3. After
24 litres of milk is added, the milk becomes twice the quantity of water. Then, 12 litres of water is added to the mixture. What is the percentage of water compared to milk in the final solution?Solution
ATQ,
Let milk = 5x litres Water = 3x litres After 24 litres of milk is added: 5x + 24 = 2 × 3x 5x + 24 = 6x x = 24 Now: Milk = 5x = 120 litres Water = 3x + 12 = 72 + 12 = 84 litres Required percentage = (84 / 120) × 100 = 70%
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