Question
The ratio of the milk to water in a mixture is 12:5. 51
litres of mixture is taken out and 12 litres of water is added in the remaining mixture. If in the resultant mixture the quantity of milk is double of the quantity of water, then find the quantity of water in the initial mixture.Solution
Let the quantity of the milk in the initial mixture = 12x litres The quantity of the water in the initial mixture = 5x litres The quantity of the milk in 51 litres of mixture = (51/17) × 12 = 36 litres The quantity of the water in 51 litres of mixture = (51/17) × 5 = 15 litres According to the question, (12x – 36) = 2 × (5x – 15 + 12) 12x – 36 = 10x – 6 2x = 30 x = 15 The quantity of the water in the initial mixture = 15 × 5 = 75 litres
1 9 64 255 755 1835
...77 ? 190 257 331 412
...18, 25, 33, 42, 52, 63, ?
15, 65, 165, 315, ?, 765
1 6 13 24 41 ?
If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...22Â Â Â 23Â Â Â Â 32Â Â Â Â 57Â Â Â 106Â Â Â ?
4Â Â Â Â Â Â Â Â Â 5.5Â Â Â Â Â Â Â Â Â Â Â 19 .5Â Â Â Â Â Â Â Â Â Â Â Â Â 98.5Â Â Â Â Â Â Â Â Â Â Â Â Â Â 694Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6251.5...
620 632 608 644 596 ?
...36, 49, 23, 62, ?, 75
