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      Question

      In a liquid solution, there is 300 ml of alcohol, which

      makes up 60% of the total volume. After removing 60 ml of the mixture, 48 ml of water is added. Then 40 ml of the new mixture is removed, and 20 ml alcohol is added. Find the difference between the quantity of alcohol and water in the final solution.
      A 85 ml Correct Answer Incorrect Answer
      B 75 ml Correct Answer Incorrect Answer
      C 61 ml Correct Answer Incorrect Answer
      D 52 ml Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      ATQ,

      Total quantity of mixture = (300 / 0.60) = 500 ml

      Quantity of water initially = 500 - 300 = 200 ml

      Ratio of alcohol to water = 300 : 200 = 3 : 2

      After removing 60 ml mixture:

      Alcohol = 300 - (3/5) × 60 = 264 ml

      Water = 200 - (2/5) × 60 + 48 = 224 ml

      After removing 40 ml mixture and adding 20 ml alcohol:

      Alcohol = 264 - (3/5) × 40 + 20 = 260 ml

      Water = 224 - (2/5) × 40 = 208 ml

      Required difference = 260 - 208 = 52 ml

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