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    Question

    In a liquid solution, there is 300 ml of alcohol, which

    makes up 60% of the total volume. After removing 60 ml of the mixture, 48 ml of water is added. Then 40 ml of the new mixture is removed, and 20 ml alcohol is added. Find the difference between the quantity of alcohol and water in the final solution.
    A 85 ml Correct Answer Incorrect Answer
    B 75 ml Correct Answer Incorrect Answer
    C 61 ml Correct Answer Incorrect Answer
    D 52 ml Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Total quantity of mixture = (300 / 0.60) = 500 ml

    Quantity of water initially = 500 - 300 = 200 ml

    Ratio of alcohol to water = 300 : 200 = 3 : 2

    After removing 60 ml mixture:

    Alcohol = 300 - (3/5) × 60 = 264 ml

    Water = 200 - (2/5) × 60 + 48 = 224 ml

    After removing 40 ml mixture and adding 20 ml alcohol:

    Alcohol = 264 - (3/5) × 40 + 20 = 260 ml

    Water = 224 - (2/5) × 40 = 208 ml

    Required difference = 260 - 208 = 52 ml

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