Question
A 400 ml mixture consists of 30% alcohol. Find how much alcohol must be added so that alcohol makes up 50% of the new mixture.
Solution
ATQ,
Alcohol in the current mixture = 0.30 × 400 = 120 ml
Let added alcohol be ‘x’ ml
So, 120 + x = 0.50 × (400 + x)
Or, 120 + x = 200 + 0.50x
Or, 0.50x = 80
So, x = 80 / 0.50 = 160 ml
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