Question
Alloy ‘X’ is formed with copper and tin in the ratio
3:5, while alloy ‘Y’ consists of tin and nickel in the ratio 2:3. If 32 grams of ‘X’ and 50 grams of ‘Y’ are mixed together, what will be the final ratio of copper, tin and nickel respectively?Solution
ATQ,
Weight of copper in 32 grams of 'X' = 32 × (3/8) = 12 grams
So, weight of tin in 32 grams of 'X' = 32 − 12 = 20 grams
Weight of tin in 50 grams of 'Y' = 50 × (2/5) = 20 grams
So, weight of nickel in 50 grams of 'Y' = 50 − 20 = 30 grams
So, total weight of tin = 20 + 20 = 40 grams
So, required ratio = 12:40:30 = 6:20:15
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