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      Question

      Alloy ‘X’ is formed with copper and tin in the ratio

      3:5, while alloy ‘Y’ consists of tin and nickel in the ratio 2:3. If 32 grams of ‘X’ and 50 grams of ‘Y’ are mixed together, what will be the final ratio of copper, tin and nickel respectively?
      A 5:15:16 Correct Answer Incorrect Answer
      B 6:20:15 Correct Answer Incorrect Answer
      C 19:12:21 Correct Answer Incorrect Answer
      D 16:15:6 Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      ATQ,

      Weight of copper in 32 grams of 'X' = 32 × (3/8) = 12 grams

      So, weight of tin in 32 grams of 'X' = 32 − 12 = 20 grams

      Weight of tin in 50 grams of 'Y' = 50 × (2/5) = 20 grams

      So, weight of nickel in 50 grams of 'Y' = 50 − 20 = 30 grams

      So, total weight of tin = 20 + 20 = 40 grams

      So, required ratio = 12:40:30 = 6:20:15

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