Question
A vessel contains 500 liters of diesel and kerosene in
the ratio 6:4. If x liters of diesel and 2x liters of kerosene are added, both become equal in volume. Find the amount of diesel left in the vessel.Solution
ATQ, Initial diesel = 500 × 6/(6 + 4) = 500 × 6/10 = 300 liters Initial kerosene = 500 – 300 = 200 liters (300 + x) / (200 + 2x) = 1/1 2x – x = 300 – 200 x = 100 The amount of diesel left = 300 + 100 = 400 liters
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