Question
A container has 500 litres of pure milk. Some quantity x
litres is removed and replaced with water. This operation is done three times in total. If after the third time, the amount of water in the container is 270.875 litres, find the value of x.Solution
ATQ, 500 × (1 – x/500)³ = 500 – 270.875 500 × ((500 – x)/500)³ = 229.125 ((500 – x)/500)³ = 229.125/500 ((500 – x)/500)³ = 229125/500000 ((500 – x)/500)³ = 1833/4000 ((500 – x)/500)³ = (15/20)³ (500 – x) = 15/20 × 500 500 – x = 375 x = 125
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