Question
200 ml of mixture A containing alcohol and water in the
ratio of 7:3 respectively is mixed with another 300 ml of mixture B containing alcohol and water in the ratio of 1:2 respectively. Find the ratio of alcohol to water in the resultant mixture.Solution
Quantity of alcohol in 200 ml of mixture A = 7/10 × 200 = 140 ml
Quantity of water in 200 ml of mixture A = 3/10 × 200 = 60 ml
Quantity of alcohol in 300 ml of mixture B = 1/3 × 300 = 100 ml
Quantity of water in 300 ml of mixture B = 2/3 × 300 = 200 ml
Desired Ratio = (140 + 100):(60 + 200) = 240:260 = 12:13
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