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Let the initial quantity of milk and water be 'y' and '2y' litres respectively.
So, (y + 1):(2y + 1) = 3:5
Or, 5 × (y + 1) = 3 × (2y + 1)
Or, 5y + 5 = 6y + 3
Or, y = 2
Therefore, required quantity = 3y = 3 × 2 = 6 litres
0.005% is equal to
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