Question
A tank has a mixture of two chemicals A and B in the ratio
2:3. After adding 10 litres of A and 5 litres of B, the new ratio becomes 4:5. What was the original volume of the mixture?Solution
ATQ,
Let A = 2y, B = 3y
(2y + 10):(3y + 5) = 4:5
⇒ 5(2y + 10) = 4(3y + 5)
⇒ 10y + 50 = 12y + 20
⇒ 2y = 30 ⇒ y = 15
Initial quantity = 2y + 3y = 5y = 5 × 15 = 75 litres
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