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    Question

    Glass S initially holds 200 ml of coke, while Glass T

    contains 110 ml of soda. First, 40 ml of coke is transferred from Glass S to Glass T. Then, 30 ml of the resulting mixture from Glass T is taken and poured back into Glass S. What is the final ratio of coke to soda in Glass S?
    A 80: 11 Correct Answer Incorrect Answer
    B 81: 11 Correct Answer Incorrect Answer
    C 88: 13 Correct Answer Incorrect Answer
    D 84: 11 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Glass S has coke = 200 ml
    On taking 40 ml, coke remaining = 200 - 40 = 160 ml
    On adding 40 ml coke in glass T, amount of mixture in glass T = 110 + 40 = 150 ml
    Ratio of coke and soda in glass T = 40: 110 = 4: 11
    Quantity of coke in 30 ml of mixture from glass T = 30 * (4/15) = 8 ml
    Quantity of soda in 30 ml of mixture from glass T = 30 * (11/15) = 22 ml
    Quantity of coke in glass S after addition of 30 ml from glass T = 160 + 8 = 168 ml
    Quantity of soda in glass S after addition of 30 ml from glass T = 22 ml
    Required Ratio = 168: 22 = 84: 11

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