Question
Two alloys are mixed in the ratio of 3:5. The first
alloy contains 60% gold, while the second alloy contains 80% gold. Find the percentage of gold in the resulting alloy.Solution
Percentage of gold in the mixture = (3 × 60 + 5 × 80) / (3 + 5) = (180 + 400) / 8 = 580 / 8 = 72.5%
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