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    Question

    Two alloys are mixed in the ratio of 3:5. The first

    alloy contains 60% gold, while the second alloy contains 80% gold. Find the percentage of gold in the resulting alloy.
    A 70% Correct Answer Incorrect Answer
    B 72% Correct Answer Incorrect Answer
    C 75% Correct Answer Incorrect Answer
    D 68% Correct Answer Incorrect Answer

    Solution

    Percentage of gold in the mixture = (3 ├Ч 60 + 5 ├Ч 80) / (3 + 5) = (180 + 400) / 8 = 580 / 8 = 72.5%

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