Question
A merchant has tea of two varieties costing Rs 200 per
kg and Rs 260 per kg. In what ratio should they be mixed so that selling the mixture at Rs 270 per kg he earns a profit of 20%?Solution
ATQ, Let cost price of mixture per kg = x. He sells at 270 with 20% profit ⇒ 270 = x(1 + 20/100) = 1.2x x = 270 / 1.2 = 225 So required mean cost = Rs 225 per kg. Use alligation between 200 and 260 to get mean 225: Higher CP = 260, lower CP = 200, mean = 225 Ratio (lower : higher) = (260 − 225) : (225 − 200) = 35 : 25 = 7 : 5 So tea at Rs 200 : tea at Rs 260 = 7 : 5.
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