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    Question

    420 ml of mixture ‘B’ contains only water and milk

    in the ratio of 7:13, respectively. If the quantity of milk in mixture ‘A’ is 20% more than that in mixture ‘B’ and equals to 40% of total quantity of mixture ‘A’ (milk + water), then find the difference between quantities of water in mixture ‘A’ and mixture ‘B’.
    A 362.4 ml Correct Answer Incorrect Answer
    B 344.4 ml Correct Answer Incorrect Answer
    C 380.4 ml Correct Answer Incorrect Answer
    D 355.4 ml Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Quantity of milk in mixture ‘B’ = (13/20) × 420 = 273 ml Quantity of water in mixture ‘B’ = (7/20) × 420 = 147 ml Quantity of milk in mixture ‘A’ = 1.20 × 273 = 327.6 ml Total quantity of mixture ‘A’ = 327.6/0.4 = 819 ml Quantity of water in mixture ‘A’ = 819 – 327.6 = 491.4 ml Required difference = 491.4 – 147 = 344.4 ml

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