The lateral surface area of a cube is 484 cm2 . The length of a cuboid is 10% more than the side of the cube. The breadth of the cuboid is 9 cm less than its length and 20% less than its height. Find the total surface area of the cuboid.
Let the length of the cube be ‘a’ cm According to the question, 4a2 = 484 => a2 = 121 => a = 11 Therefore, length of the cuboid = l = 1.1 × 11 = 12.1 cm Breadth of the cuboid = b = 12.1 – 9 = 3.1 cm Height of the cuboid = h = 3.1/0.8 = 3.875 cm Therefore, total surface area of the cuboid = 2(lb + bh + lh) = 2 × {(12.1 × 3.1) + (3.1 × 3.875) + (12.1 × 3.875)} = 192.82 cm2
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