Question
A rectangular field is 40 m long and 25 m wide. Find the
cost of fencing it three times all around at the rate of Rs. 12 per metre.Solution
Perimeter of rectangle = 2(L + B) = 2(40 + 25) = 2 × 65 = 130 m Length of fencing for 3 rounds = 3 × 130 = 390 m Cost = 390 × 12 = 4680 Answer: Rs. 4680
∆ PQR is right-angled at Q. If ∠R = 60º, then find the value of cosec P.
If tan² 45°- cos² 60° x sin 45° cos 45° cot 30°, then find the value of 'x'.
The value of (3tan10°-tan³10°)/(1-3tan²10°) is equal to
- If sin (4A − B) = (√2/2) and cos (A + B) = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’.
sin2 7 ° + sin2 8 ° + sin2 9 ° + sin2 10 ° + ……… + sin2 83 ° = ?
...If cos1.5B = sin(B + 5°), then find the measure of 'B'.
- If sin(A + B) = 1/2 and cos(A + 2B) = √3/2, where 0° < A, B < 90°, then find the value of tan(2A).

cos (sec-1 x) is equal to –
If A + B = 450 , then the value of 2(1 + tanA) (1 + tanB) is: