Question
A right circular cone has a height that is double its
radius, and its volume is measured at 2,250Ï€ cm³. If the radius is reduced to one-third and the height to half of their original sizes, what would be the new volume of the cone?ÂSolution
Let the radius of right circular cone be 'R' cm. So, height of cone = '2R' cm Volume of a right circular cone = (1/3) X π X (radius) 2 X height So, (1/3) X π X R2 X 2R = 2,250π Or, R3 = 3,375 Or, 'R' = 15 cm Height of cone = 2 X 15 = 30 cm New radius of cone = (15/3) = 5 cm New height of cone = (30/2) = 15 cm So, required volume = (1/3) X π X 52 X 15 = 125π cm3
Evaluate: 96 ÷ {8 + 4 × 2} + 15
Simplify the following expressions and choose the correct option.
(7/9) of [81 − {36 ÷ (4 + 2)}] = ?
(13 X 11) + (19 X 3) = 400% of √?
- Calculate the value of the following expression:
Simplify the following expressions and choose the correct option.
[560 ÷ 7 - (3/8 of 128)] + [2/3 of 171 - 52]
What will come in the place of question mark (?) in the given expression?
(40/25) X 80 - ? = 45% of 300 - 55
400 % of 20 + 65 % of 620 - 92 × 5 = ?
180 ÷ 3 of 2 = 102 – ?
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