Question
The volume of a cone is 8192 π cm3. The
height of the cylinder is 35% more than the slant height of the cone. The lateral surface area of the cylinder is 4536 π cm2. If the base area of the cone is 1024 π cm2, then find out the volume of the cylinder (in cm 3).Solution
If the base area of the cone is 1024 π cm2.  π x (radius of the cone)2 = 1024 π   Eq.(i) radius of the cone = 32 cm [Here negative value is not possible.] The volume of a cone is 8192 π cm3. (⅓) x π x (radius of the cone)2 x height of the cone = 8192 π Put Eq.(i) in the above equation. (⅓) x height of the cone = 8 height of the cone = 24 cm  Eq.(ii) (slant height of the cone)2 = (radius of the cone)2 + (height of the cone)2 (slant height of the cone)2 = (32)2 + (24)2 = 1024+576 = 1600 slant height of the cone = 40 cm The height of the cylinder is 35% more than the slant height of the cone. height of the cylinder = (100+35)% of 40 height of the cylinder = 135% of 40 = 54 cm The lateral surface area of the cylinder is 4536 π cm2. 2 x π x radius of the cylinder x height of the cylinder = 4536 π radius of the cylinder x 54 = 2268 radius of the cylinder = 42 Volume of the cylinder = π x (radius of the cylinder)2 x height of the cylinder = π x (42)2 x 54 = (22/7) x 1764 x 54 = 22 x 252 x 54 = 299376 cm3
Statements: M % C & G @ T $ D; W % M # PÂ
Conclusions :Â Â Â Â Â I. D % CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. M % GÂ Â Â Â Â Â Â Â Â Â Â Â Â ...
Statements: G > N > P = E ≥ H < L; M < E < B < C = Q > X; U > W > Y = Q > H
Conclusions:
I). U > P
II). Y > P
...Statements: A > B; C > D; E ≥ A; F = C; C < B
Conclusions:
(i) B > D (ii) A > F (iii) F < E
...Which of the following symbols should replace the question mark in the given statement in order to make conclusion 'B>Z' as well as 'C>X' definitely tr...
Statements: F % W, W © R, R @ M, M $ D
Conclusions:
 I.D @ R                               II.M $ F�...
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ B ≤ K
Conclusions:I. K > F II. K = F
Statements:  B > K < Y, E > C ≥ O = Y
Conclusions:
I. C > B
II. E ≤ Y
III. E > K
IV. O ≥ K
...Statements: B > D = C ≥ E ≥ G, C = H ≤ I < F
Conclusions:
I. B > H
II. I ≥ G
III. F > DStatement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > EÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. H > K
...Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
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