Question
The perimeter of a rectangle is 110% more than perimeter
of a square of side 20 cm. If the length of rectangle is 240% more than side of square then find the difference between the area of square and the area of rectangle.Solution
Perimeter of the square = 4 x 20 = 80 cm Perimeter of the rectangle = 80 x (210/100) = 168 cm Length of the rectangle = 20 x (340/100) = 68 cm Let the breadth of the rectangle be b cm. => 2 x (68 + b) = 168 => b = 84 – 68 => b = 16 cm Required difference = (68 x 16) - (20 x 20) = 688
More Mensuration Questions
?% of 1499.89 + 54.14 × 8 = 25.05% of 5568.08
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
? + 163.99 – 108.01 = 25.01 × 6.98
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
(15.15 ×  31.98) + 30.15% of 719.99 = ? + 124.34
(124.99)² = ?
6.992 + (2.01 × 2.98) + ? = 175.03
(627.98 ÷ 3.98 + 11.01 X 12.98 - ?) ÷ √623 = (178.98 + 37.08) ÷ 23.98Â
