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    Question

    The perimeter of a rectangle is 110% more than perimeter

    of a square of side 20 cm. If the length of rectangle is 240% more than side of square then find the difference between the area of square and the area of rectangle.
    A 688 Correct Answer Incorrect Answer
    B 285 Correct Answer Incorrect Answer
    C 400 Correct Answer Incorrect Answer
    D 344 Correct Answer Incorrect Answer

    Solution

    Perimeter of the square = 4 x 20 = 80 cm Perimeter of the rectangle = 80 x (210/100) = 168 cm Length of the rectangle = 20 x (340/100) = 68 cm Let the breadth of the rectangle be b cm. => 2 x (68 + b) = 168 => b = 84 тАУ 68 => b = 16 cm Required difference = (68 x 16) - (20 x 20) = 688

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