Question
The perimeter of a rectangle is 130% more than perimeter
of a square of side 10 cm. If the length of rectangle is 250% more than side of square then find the difference between the area of square and the area of rectangle.Solution
Perimeter of the square = 4 x 10 = 40 cm Perimeter of the rectangle = 40 x (230/100) = 92 cm Length of the rectangle = 10 x (350/100) = 35 cm Let the breadth of the rectangle be b cm. => 2 x (35 + b) = 92 => b = 46 – 35 => b = 11 cm Required difference = (35 x 11) - (10 x 10) = 285
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
I. 96y² - 76y – 77 = 0
II. 6x² - 19x + 15 = 0
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0
I. 4x² - 21 x + 20 = 0
II. 8y² - 22 y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. Â 2(x+2)+ 2(-x)=5
II. Â (1/(y+1)+ 1/(y+5))=(1/(y+2)+ Â 1/(y+4))
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0�...
 If x satisfies x² – 14x + 40 = 0, find x.
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
