Question
Quantity of water in a 320 litres mixture (alcohol +
water) is 20 litres less than the quantity of alcohol in it. Find the quantity of water to be mixed so that the quantity of alcohol in the mixture becomes 50% of the whole mixture.Solution
Quantity of water in the mixture = (320 β 20)/2 = 150 litres So, Quantity of alcohol in the mixture = (320 β 150) = 170 litres Total quantity of the mixture = 170 x (100/50) = 340 litres Therefore, quantity of water to be mixed = 340 β 320 = 20 litres
564.932 + 849.029 β 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of βΉ60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to βΉ75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 Γ· 40.48 Γ 10.12 = ? Γ 2.16
(124.901) Γ (11.93) + 219.95 = ? + 114.891 Γ 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...