Question
Quantity of water in a 320 litres mixture (alcohol +
water) is 20 litres less than the quantity of alcohol in it. Find the quantity of water to be mixed so that the quantity of alcohol in the mixture becomes 50% of the whole mixture.Solution
Quantity of water in the mixture = (320 – 20)/2 = 150 litres So, Quantity of alcohol in the mixture = (320 – 150) = 170 litres Total quantity of the mixture = 170 x (100/50) = 340 litres Therefore, quantity of water to be mixed = 340 – 320 = 20 litres
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