Question
Two mixtures (milk and water) 'A' and 'B' contains
quantities of milk and water in ratio of 4:5 and 7:8, respectively. If 36 ml from 'A' and 45 ml from 'B' are mixed to form a new mixture, then find the percentage (approximately) of water in the new mixture.Solution
Quantity of water in 36 ml of mixture 'A' = 36 X (5/9) = 20 ml Quantity of water in 45 ml of mixture 'B' = 45 X (8/15) = 24 ml Total quantity of final mixture = (36 + 45) = 81 ml Required percentage = ((20 + 24) ÷ 81} X 100 = 54.3%
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