136 litres of mixture ‘A’ (milk + water) contains 32

Solution

Let the quantity of milk in mixture ‘A’ = ‘y’ litres Then, quantity of water in mixture ‘A’ = (y + 32) litres So, y + y + 32 = 136 Or, 2y = 136 – 32 = 104 Or, y = 104/2 = 52 So, quantity of milk in mixture ‘A’ = 52 litres And, quantity of water in mixture ‘A’ = 52 + 32 = 84 litres Quantity of milk in 25% of mixture ‘A’ = 52 × 0.25 = 13 litres Quantity of water in 25% of mixture ‘A’ = 80 × 0.25 = 20 litres So, quantity of milk in the jar = 13 + 70 = 83 litres Quantity of water in the jar = 80 + 20 = 100 litres So, required percentage = (83/100) × 100 = 83%