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      Question

      136 litres of mixture β€˜A’ (milk + water) contains 32

      litres more water than milk. If 25% of mixture β€˜A’, 70 litres of milk and 80 litres of water are added in an empty jar, then the quantity of milk is what percentage of the quantity of water in the jar?
      A 63% Correct Answer Incorrect Answer
      B 73% Correct Answer Incorrect Answer
      C 93% Correct Answer Incorrect Answer
      D 83% Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      Let the quantity of milk in mixture β€˜A’ = β€˜y’ litres Then, quantity of water in mixture β€˜A’ = (y + 32) litres So, y + y + 32 = 136 Or, 2y = 136 – 32 = 104 Or, y = 104/2 = 52 So, quantity of milk in mixture β€˜A’ = 52 litres And, quantity of water in mixture β€˜A’ = 52 + 32 = 84 litres Quantity of milk in 25% of mixture β€˜A’ = 52 Γ— 0.25 = 13 litres Quantity of water in 25% of mixture β€˜A’ = 80 Γ— 0.25 = 20 litres So, quantity of milk in the jar = 13 + 70 = 83 litres Quantity of water in the jar = 80 + 20 = 100 litres So, required percentage = (83/100) Γ— 100 = 83%

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