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      Question

      If 4 kg of metal of which 1/3rd is zinc and

      the rest is copper, be mixed with 5kg of metal, of which 1/6 is zinc and the rest is copper, then what will be the ratio of zinc to copper in the mixture?
      A 23:31 Correct Answer Incorrect Answer
      B 13:41 Correct Answer Incorrect Answer
      C 31:41 Correct Answer Incorrect Answer
      D 41:27 Correct Answer Incorrect Answer
      E 31:14 Correct Answer Incorrect Answer

      Solution

      In the first metal mixture: Quantity of zinc = 4 × (1/3) = 4/3 kg Quantity of copper = 4 – 4/3 = 8/3 kg In the second metal mixture: Quantity of zinc = 5 × (1/6) = 5/6 kg Quantity of copper = 5 – 5/6 = 25/6 kg Total quantity of zinc in the mixture = 4/3 + 5/6 = 8/6 + 5/6 = 13/6 kg Total quantity of copper in the mixture = 8/3 + 25/6 = 16/6 + 25/6 = 41/6 kg Therefore, required ratio of zinc to copper = 13/6 : 41/6 = 13 : 41

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