Question
A jug initially contains 80 liters of a mixture of milk
and chocolate, with the quantity of chocolate being 30% of the total mixture. A liters of the mixture is taken out and replaced by chocolate, and the same quantity is repeated once more. If the final quantity of milk in the jug is 31.5 liters, what is the value of A?Solution
ATQ, we can say that, Milk in 80 liters = 80 × 70/100 = 56 liters chocolate in 80 liters = 80 × 30/100 = 24 liters 31.5 = 56 × (1 – x/80)2 4.5/8 = (1 – x/80)2 4.5 × 80 × 80 / 8 = (80 – x)2 60 = 80 – x x = 20 liters
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will replace the question mark (?) in the following?
? =...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
14.96% of 120.03 - 107.99 + 88.93% of 199.87 = ?
16.98 × 88.05 + 1999.996% of 299.08 + 5.005 % of 4999.997 = ? × 20.98 × 40.009
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
?% of (150.31 ÷ 14.97 × 50.011) = 319.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(363.89% of 224.98 – 319.86% of 134.94) ÷ ? = √(134.88 ÷ 15.25)
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