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    Question

    If in a ΔABC, AD is internal angle bisector & D is a

    point on BC, AB = 5cm, BC = 7cm then what is BD:CD?
    A 5:2 Correct Answer Incorrect Answer
    B 7:5 Correct Answer Incorrect Answer
    C 2:5 Correct Answer Incorrect Answer
    D 2:7 Correct Answer Incorrect Answer

    Solution

    By Internal angle bisector theorem, AB:AC = BD:CD So, 5: x = BD:CD => 5 + x = BC [BD+CD = BC] => 5 + x = 7 => x = 2 BD:CD = 5:2

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