Question
If perpendicular and base of a right-angle triangle are
24 cm and 32 cm respectively, then find the length of the shortest median of triangle.Solution
Using Pythagoras theorem, (Perpendicular)² + (Base)² = (Hypotenuse)² Or, 24² + 32² = (Hypotenuse)² Or, (Hypotenuse)² = 576 + 1024 = 1600 So, Hypotenuse = 40 cm Shortest median of a right-angle triangle = Circumradius = (Hypotenuse/2) = (40/2) = 20 cm Hence, option C.
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