Question
If perpendicular and base of a right-angle triangle are
30 cm and 40 cm respectively, then find the length of the shortest median of triangle.Solution
Using Pythagoras theorem, (Perpendicular)² + (Base)² = (Hypotenuse)² Or, 30² + 40² = (Hypotenuse)² Or, (Hypotenuse)² = 900 + 1600 = 2500 So, Hypotenuse = 50 cm Shortest median of a right-angle triangle = Circumradius = (Hypotenuse/2) = (50/2) = 25 cm Hence, option A.
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DI-NS-XC...
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23Â 28Â 38Â 53Â 73Â ?
Which two signs should be interchanged to make the following equation correct?
18 − 23 × 455 ÷ 7 + 28 = 377
