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ATQ,
Let the length of each edge of the cube = ‘a’ cm
So, 6 × a² = 216
So, a² = 36
Or, a = 6
So, length of the cuboid = 2 × a = 2 × 6 = 12 cm
Width of the cuboid = a = 6 cm
And, height of the cuboid = a = 6 cm
Desired area = 2 × (6 × 6 + 6 × 12 + 6 × 12) = 2 × 216 = 432 cm²
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