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ATQ, Let the length and breadth of the park be ‘L’ metres and ‘B’ metres, respectively. Perimeter of the park = (540/9) = 60 metres So, 2 × (L + B) = 60 Or, (L + B) = 30 ATQ; L = B + 6 So, B + 6 + B = 30 Or, 2B = 24 So, B = 12 So, breadth of the park = 12 metres And, length of the park = 12 + 6 = 18 metres So, area of the park = 18 × 12 = 216 m²
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