New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    If tan θ + cot θ = 5, then the value of

    tan2 θ + cot2 θ + 2tan2 60° is:
    A 29√3 Correct Answer Incorrect Answer
    B 29 Correct Answer Incorrect Answer
    C 25 Correct Answer Incorrect Answer
    D 10√3 Correct Answer Incorrect Answer

    Solution

    tan θ + cot θ = 5 Squaring both sides ⇒ tan2 θ + cot2 θ + 2 tanθ cotθ = 25 ⇒ tan2 θ + cot2 θ = 25 - 2 ⇒ tan2 θ + cot2 θ = 23 tan2 θ + cot2 θ + 2 tan2 60° ⇒ 23 + 2 × (√3)2 ⇒ 23 + 2 × 3 ⇒ 29

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