Question
If an arc subtends an angle of 90o at the
centre of the circle whose radius is 28 cm, then find the area of that sector. [Take π = 22/7]Solution
Area of the sector = (θ/360) × π × r2 [Where ‘θ’ is the angle subtended by the minor arc and ‘r’ is the radius of the circle] Desired area = (90/360) × (22/7) × 28 × 28 = 616 cm2
Identify the logic of the below given series and given answer.
Series I :: 81, 89, 116, 241, (A), 1915
Series II :: (B), 204, 208, 4...
18Â Â Â Â Â Â Â Â Â Â 434Â Â Â Â Â Â Â Â 642Â Â Â Â Â Â Â Â 746Â Â Â Â Â Â Â Â 798Â Â Â Â Â Â Â Â ?
...10, 22, 46, ?, 130, 190
12, 20, 36, ?, 132, 260
8Â Â Â Â 20Â Â Â Â 36Â Â Â Â Â 56Â Â Â Â Â 80Â Â Â Â ?
If 152,   242,    x ,  332,   404,    314,
then find the value of (2x – 1)?
...21, 22, 48, 153, 628, ?
30Â Â Â Â Â Â 15Â Â Â Â Â Â Â 15Â Â Â Â Â Â Â 30 Â Â Â Â Â Â Â 120Â Â Â Â Â Â Â ?
...48Â Â Â Â 61 Â Â Â Â 76 Â Â Â Â 94Â Â Â Â 116 Â Â Â Â Â ?
If 4 2 x 1.5 0.5
Then, 1/3 x + 2.5 = ?
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