Question
The perimeter of a square field is 14 cm more than the
perimeter of a rectangle. The length of the rectangle is 49 cm which is 350% of its width. If a street of width 10 cm surrounds from outside the square, then find the total cost of constructing the street at the rate of Rs. 25 per sq. cm?Solution
Let the width of the rectangle = x cm Then, 350% of x = 49 x = 49 × 100/350 = 14 cm Perimeter of the rectangle = 2(length + width) = 2 × (49 + 14) = 126 cm Perimeter of the square = (126 + 14) = 140 cm The sides of the square = 140/4 = 35 cm The area of the square field without street = (35)2 sq. cm = 1225 sq. cm The area of the square field with street = (35 + 20)2 sq. cm = 3025 sq. cm The area of the street = 3025 – 1225 = 1800 sq. cm The total cost of constructing the street = 1800 × 25 = Rs. 45,000
Β If the PV ratio us 80% and MOS is 20000. Calculate FC if SP per unit is 5 and Contribution is 40000.
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