Question
 A path of width 3 m is made outside and around a
rectangular field of perimeter 210 m. If the length of the field is 50% more than its breadth, then find the cost of paving the path at Rs. 15 per m².Solution
ATQ, Let, breadth of the field be ‘x’ m. So, the length of the field = ‘1.5x’ m. Therefore, 2 × (x + 1.5x) = 210 2.5x = 105 x = 42 Therefore, the breadth of the field = x = 42 metres. Length of the field = 1.5x = 63 metres. So, the area of the path = (69 × 48) – (42 × 63) = 3312 – 2646 = 666 m². Required cost = 666 × 15 = Rs.9990
Simplify: 48 ÷ 4 × 3 + 5 × (6 − 2)
17.5% of 400 – 24% of 150 = ?
125% of 129 ÷ 43 × 28 ÷ 7 = ? ÷ √16
(5.6 + 2.4 + 13.8 – 2.8) × 5 = ? × (12.5 – 7.5)
(3/7) of 700 + 33(1/3)% of 339 - 69 =?
? = 15% of 2400 + 140% of 4200 – 12 3Â
6% of 520 + 5% of 620 = ?
What will come in the place of question mark (?) in the given expression?
(12.09)2 × 5.98 ÷ 26.95 = ? + 25Â
1231 + 1312 + 2113 – 3211 = ?
√ 729 × 5 – 220 % of 15 + ? = 120% of 160