Question
The area of the rectangular field is 720 m² and its
perimeter is 106 m. Find how much percent less the breadth of the field is compared to the length of the field?Solution
ATQ, Let the length and the breadth of the rectangular field be ‘l’ meter and ‘b’ meter, respectively. So, the area of the rectangular field = l × b = 720 l = 720/b Perimeter of the rectangular field = 2(l + b) = 106 l + b = 53 720/b + b = 53 720 + b² = 53b b² – 53b + 720 = 0 b² – 40b – 13b + 720 = 0 b(b – 40) – 13(b – 40) = 0 (b – 13)(b – 40) = 0 b = 40, 13 b = 13 m and l = 40 m as length is greater than breadth So, the desired percentage = {(40 – 13)/40} × 100 = 67.5%
35Â Â Â Â Â Â Â Â Â Â 36Â Â Â Â Â Â Â Â Â Â 40Â Â Â Â Â Â Â Â Â Â 49Â Â Â Â Â Â Â Â Â Â 65Â Â Â Â Â Â Â Â Â Â ?
...If   20       x      46      147       604        3045
Then, x% of 25 = ?
...10 625 50 125 250 25 ?
...2, 12, 36, 80, ?, 252
69    119    156    ?     199    209
15 , 33 , 71 , 150 , 307 , 625
52 25 27 ? 208 1648
...1400      350       700       175        ?       87.5
...7Â Â Â Â Â 14Â Â Â Â Â 42Â Â Â Â Â 168Â Â Â Â Â Â 840Â Â Â Â Â ?
...729 512 343 216 125 ?
...
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