The area of the rectangular field is 720 m² and its perimeter is 106
m. Find how much percent less the breadth of the field is compared to the length of the field?

ATQ, Let the length and the breadth of the rectangular field be ‘l’ meter and ‘b’ meter, respectively. So, the area of the rectangular field = l × b = 720 l = 720/b Perimeter of the rectangular field = 2(l + b) = 106 l + b = 53 720/b + b = 53 720 + b² = 53b b² – 53b + 720 = 0 b² – 40b – 13b + 720 = 0 b(b – 40) – 13(b – 40) = 0 (b – 13)(b – 40) = 0 b = 40, 13 b = 13 m and l = 40 m as length is greater than breadth So, the desired percentage = {(40 – 13)/40} × 100 = 67.5%