Question
The height of a sphere is 28 cm.
Find the surface area of the given sphere. (Take π = 22/7)Solution
ATQ, Surface area of sphere = 4 × π × radius² Height of sphere = Diameter of sphere So, radius of the given sphere = 28 ÷ 2 = 14 cm So, required area = 4 × (22/7) × 14² = 2464 cm²
Find the smallest multiple of 10 that, when divided by 4, 6, and 9, leaves a remainder of 4 in each case.
Two numbers have LCM 360 and HCF 12. If one of the numbers is 72, find the other number. Also find how many common divisors the two numbers have.
Find the difference between sum of digits of LCM and HCF of 32, 48 and 80.
Find the HCF of 36, 108, and 156.
The HCF of two numbers is 7. Which of the following can never be their LCM?
Find the greatest number that will divide 420, 525 and 300 without leaving a remainder.
The HCF of two numbers is 13. Which of the following can never be their LCM?
The greatest number, which when subtracted from 6254, gives a number exactly divisible by each of 20, 25, 30 and 35, is:
The HCF and LCM of two natural numbers are 8 and 48, respectively. What is the difference between the two numbers, if one of the numbers is 16?
What is the Highest Common Factor of 54, 162 and 270?
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