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    Question

    In what time would a Cistern be filled by three pipes

    whose diameter are 2cm, 8/3 cm and 4cm running together, where the largest pipe alone fill it in 183 minutes. The amount of water flowing in by each pipe being proportional to the square of diameter?
    A 72 minutes Correct Answer Incorrect Answer
    B 110 minutes Correct Answer Incorrect Answer
    C 140 minutes Correct Answer Incorrect Answer
    D 206 minutes Correct Answer Incorrect Answer
    E 108 minutes Correct Answer Incorrect Answer

    Solution

    1stPipe 2ndPipe 3rdPipe Diameter 2 8/3 4 6 8 12 3 : 4 : 6 Efficiency proportional to the Square of the diameter 9 : 16 : 36 Total efficiency = 9 + 16 + 36 = 61 Pipe 3rdcan fill the cistern in 183 minutes (given) Therefore, the capacity of the Tank = (36 × 183) = 6588 Now, the Time taken by all pipes together = 6588/61 = 108 minutes

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