Question
The area of the rectangular field is 480 mΒ² and its
perimeter is 88 m. Find how much percent less the breadth of the field is compared to the length of the field?Solution
ATQ, Let the length and the breadth of the rectangular field be βlβ meter and βbβ meter, respectively. So, the area of the rectangular field = l Γ b = 480 l = 480/b Perimeter of the rectangular field = 2(l + b) = 88 l + b = 44 480/b + b = 44 480 + bΒ² = 44b bΒ² β 44b + 480 = 0 bΒ² β 30b β 14b + 480 = 0 b(b β 30) β 14(b β 30) = 0 (b β 14)(b β 30) = 0 b = 30, 14 b = 14 m and l = 30 m as length is greater than breadth So, the desired percentage = {(30 β 14)/30} Γ 100 = 53.33%
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