Question
A tree breaks due to a storm and the top touches the
ground 30 meters away from its base, making a 30-degree angle with the ground. What was the height of the tree before it broke?Solution
The height of the tree before it broke =AB+AC trigonometry (tan) = opposite/adjacent): tan 30Β° = AB/30 Since tan 30Β° = 1/β3 1 /β3 =AB/30 AB=30/β3 =10β3m AB = 10β3 Cos 30Β° =BC/AC β3 /2 =30 /AC AC =60 /β3 AC =20β3. Now the height of the tree=AB+AC =10β3 +20β3 =30β3
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