Question
A tree breaks due to a storm and the top touches the ground 30 meters away from its base, making a 30-degree angle with the ground. What was the height of the tree before it broke?
The height of the tree before it broke =AB+AC trigonometry (tan) = opposite/adjacent): tan 30° = AB/30 Since tan 30° = 1/√3 1 /√3 =AB/30 AB=30/√3 =10√3m AB = 10√3 Cos 30° =BC/AC √3 /2 =30 /AC AC =60 /√3 AC =20√3. Now the height of the tree=AB+AC =10√3 +20√3 =30√3 More Height and Distance Questions
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