Find the least number of four digits which is exactly divisible by 6, 24 and 32?
Least four digit number = 1000 So when 1000 is divided by LCM of 6,24 & 32 (i.e.96), remainder is 40. So when gap of divisor & remainder is added to 1000, it will be completely divided by 96 & answer will be = 1000 + (96-40) = 1000 + 56 = 1056.
If a nine-digit number 785x3678y is divisible by 72, then the value of (x − y) is:
What will be the remainder when 742 is divided by 48?
Find the remainder when 23 x 34 x 45 x 56 x 67 x 78 is divided by 11.
A five-digit number 2A78B, is divisible by 55. What is the difference between the maximum and minimum possible value of (A-B)?
Which of the following pairs of non-zero values of p and q make 6-digit number 674pq0 divisible by both 3 and 11?
What is the smallest perfect square that is divisible by each of 42, 48 and 60?
The largest three-digit number which gives the same remainder 1 when divided by 4, 9, 6 is:
What are the last two digits of 56283 x 141283 × 125254?
