Question
The LCM of the two numbers is 12 times their HCF. The
sum of LCM and HCF is 429 and if both the number are smaller than their LCM. Find both numbers.Solution
LCM =12 HCF LCM: HCF = 12:1 ATQ-      13 = 429 1 = 33 HCF = 33 LCM = 33×12 = 396 Let the no 33x and 33y. As we know the product of two numbers = product of HCF & product of LCM 33x ×33y = 33 ×33×12 x y = 12 We cannot take values of x & y = 2 & 6 because these have 2 in common extra but there must be nothing common as 12 HCF is already taken. If values of x, y is (1, 12) ⇒ 1 × 33 = 33, 33 × 12 = 396 → not less than LCM If values of x, y is (3, 4) ⇒ 3 × 33, 4 × 33 = 99, 132.
1, 2, 3, 4, 5 and 6 are written on different faces of a dice. Three different positions of the same dice are shown below. Find the number on the face op...
Ten people are sitting in two parallel rows 1 and 2. A, B, C, D and E are sitting in row 1 facing south, and V, W, X, Y and Z are sitting in row 2 facin...
Six friends are sitting in a circle facing the centre of the circle. Veena and Sadvi are the immediate neighbours of Pooja. Anil and Guna are the immedi...
A question is given, followed by two statements labelled I and II. Identify which of the statements is/are sufficient/necessary to answer the question.�...
Identify the figure given in the options which when put in place of the question mark (?) will logically complete the series?
Select the number from the given options which can come in place of the question mark (?) in the following equation.Â
74.96 ÷ 14.998 × 7.007 +...
P is to the north of Q. T is to the east of Q and S is to the east of P. S is to the northeast of T and south-west of R. What is the position of R with ...
If Z # L @ P & K @ J # X, then how is K related to Z?
Select the set in which the numbers are related in the same way as are the numbers of the following sets.
(NOTE: Operations should be performed o...
In the following number-pairs, the second number is obtained by applying some mathematical operations on the first number. Select the option in which t...