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    Question

    The sum of two numbers is 126 and their HCF is 14. Total

    number of such pairs of numbers is?     
    A 3 Correct Answer Incorrect Answer
    B 4 Correct Answer Incorrect Answer
    C 2 Correct Answer Incorrect Answer
    D 6 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    As HCF is 14 so let numbers be 14x & 14y. It means x & y must be co-prime. Now 14x+ 14y = 126, So x + y = 9. Now pairs of (x , y) can be (1,8) , (2,7) , (3, 6) & (4,5) but (3,6) is not co-prime hence number of pairs are 3. 

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