Question
The sum of two numbers is 126 and their HCF is 14. Total
number of such pairs of numbers is?  ÂSolution
As HCF is 14 so let numbers be 14x & 14y. It means x & y must be co-prime. Now 14x+ 14y = 126, So x + y = 9. Now pairs of (x , y) can be (1,8) , (2,7) , (3, 6) & (4,5) but (3,6) is not co-prime hence number of pairs are 3.Â
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