Question
The HCF of two numbers is 18 and their LCM is 540. If one of the numbers is 90, find the other number.
Solution
For two numbers a and b: a × b = HCF × LCM So, 90 × b = 18 × 540 18 × 540 = (18 × 54) × 10 = 972 × 10 = 9720 Thus b = 9720 / 90 = 108 Answer: The other number is 108.
More HCF and LCM Questions
- Find the smallest multiple of 10 that, when divided by 4, 6, and 9, leaves a remainder of 4 in each case.
- Find the HCF and LCM of 18 and 30.
- Find the largest number of the five digit which is exactly divisible by 48, 72 and 108.
- The sum of two numbers is 99 and their HCF is 9. Total number of such pairs of numbers is?
- The least number which when divided by 4, 6, 10 and 12 leave zero remainder in each case and when divided by 13 leaves a remainder of 8 is:
- The product of the two prime numbers is 187. What will the L.C.M of these two numbers?
- Find the difference between sum of digits of LCM and HCF of 25, 50 and 75.
- Find the HCF of 932 and 748.
- The LCM of two numbers is 168, and the numbers are in the ratio 4:7. Find the sum of the numbers.
- The HCF of two numbers is 12. If their product is 1728, then how many such pairs exist?
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