Question
What will be the greatest common divisor (GC
- D of (x² - 8x + 15) and (x² - 11x + 30).
Solution
(x² - 8x + 15) = x² - 5x - 3x + 15 = x(x - 5) - 3(x - 5) = (x - 5)(x - 3) x² - 11x + 30 = x² - 5x - 6x + 30 = x(x - 5) - 6(x - 5) = (x - 5)(x - 6) So, required GCD = (x - 5) Hence, option b.
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