Question
Find the largest four-digit number which when divided
by each of 18, 21 and 24 leaves a remainder of 7.Solution
LCM of 18, 21 and 24. 504 Largest four-digit number = 9999 Largest four-digit number divided by 504. =9999/504 = 19.83 So, the desired number according to the question is. = 504×19+7=9583
(500 × 6 ÷ 10) - (√256 + 8) = ?
22% of 400 + √ ? = 34% of 800 - 25% of 400
(2/5)(32% of 4500 – 440) = ? × 8
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
What will come in the place of question mark (?) in the given expression?
96 ÷ (9 - 6.6) + 17.5 X 6 = ? ÷ 8
13 X ? = 85 X 4 + √81 + 2
45% of 360 - 160 + ? = √324
((67)32 × (67)-18 / ? = (67)⁸
4567.89 - 567.89 - 678.89 = ?
82.3 × 644.7 × 723.4 × 815.85 = 72?