Question
Two numbers are in the ratio 2:8. The product of their
H.C.F. and L.C.M. is 3600. The sum of the numbers is:Solution
Let the numbers be 2x and 8x respectively. First number × second number = HCF × LCM => 2x × 8x = 3600 => x2 = [3600/(2×8)] = 225 => x = √225 = 15 Sum of the numbers = 2x + 8x = 10x = 10 × 15 = 150
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